0=-x^2+6x+432

Solution for 0=-x^2+6x+432 equation:

0=-x^2+6x+432

We move all terms to the left:

0-(-x^2+6x+432)=0

We add all the numbers together, and all the variables

-(-x^2+6x+432)=0

We get rid of parentheses

x^2-6x-432=0

a = 1; b = -6; c = -432;
Δ = b2-4ac
Δ = -62-4·1·(-432)
Δ = 1764
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1764}=42$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-42}{2*1}=\frac{-36}{2}
=-18
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+42}{2*1}=\frac{48}{2}
=24
$